2 This is an interactive tutorial. To let you interact on line with the system,
3 you must first of all register yourself.
5 Before starting, let us briefly explain the meaning of the menu buttons.
6 With the Advance and Retract buttons you respectively perform and undo single
7 computational steps. Each step consists in reading a user command, and processing
8 it. The part of the user input file (called script) already executed by the
9 system will be colored, and will not be editable any more. The advance bottom
10 will also automatically advance the focus of the window, but you can inspect the
11 whole file using the scroll bars, as usual. Comments are skipped.
12 Try to advance and retract a few steps, to get the feeling of the system. You can
13 also come back here by using the top button, that takes you at the beginning of
14 a file. The play button is meant to process the script up to a position
15 previously selected by the user; the bottom button execute the whole script.
16 That's it: we are
\ 5span style="font-family: Verdana,sans-serif;"
\ 6 \ 5/span
\ 6now ready to start.
18 The first thing to say is that in a system like Matita's very few things are
19 built-in: not even booleans or logical connectives. The main philosophy of the
20 system is to let you define your own data-types and functions using a powerful
21 computational mechanism based on the declaration of inductive types.
23 Let us start this tutorial with a simple example based on the following well
26 \ 5h2 class="section"
\ 6The goat, the wolf and the cabbage
\ 5/h2
\ 6A farmer need to transfer a goat, a wolf and a cabbage across a river, but there
27 is only one place available on his boat. Furthermore, the goat will eat the
28 cabbage if they are left alone on the same bank, and similarly the wolf will eat
29 the goat. The problem consists in bringing all three items safely across the
32 Our first data type defines the two banks of the river, which will be named east
33 and west. It is a simple example of enumerated type, defined by explicitly
34 declaring all its elements. The type itself is called "bank".
35 Before giving its definition we "include" the file "logic.ma" that contains a
36 few preliminary notions not worth discussing for the moment.
39 include "basics/logic.ma".
41 inductive bank: Type[0] ≝
45 (* We can now define a simple function computing, for each bank of the river, the
48 definition opposite ≝ λs.
50 [ east ⇒
\ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6
51 | west ⇒
\ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,1,0)"
\ 6east
\ 5/a
\ 6
54 (* Functions are live entities, and can be actually computed. To check this, let
55 us state the property that the opposite bank of east is west; every lemma needs a
56 name for further reference, and we call it "east_to_west". *)
58 lemma east_to_west :
\ 5a href="cic:/matita/tutorial/chapter1/opposite.def(1)"
\ 6opposite
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,1,0)"
\ 6east
\ 5/a
\ 6 \ 5a title="leibnitz's equality" href="cic:/fakeuri.def(1)"
\ 6=
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6.
60 (* If you stop the execution here you will see a new window on the right side
61 of the screen: it is the goal window, providing a sequent like representation of
68 -----------------------
71 for each open goal remaining to be solved. A is the conclusion of the goal and
72 B1, ..., Bk is its context, that is the set of current hypothesis and type
73 declarations. In this case, we have only one goal, and its context is empty.
74 The proof proceeds by typing commands to the system. In this case, we
75 want to evaluate the function, that can be done by invoking the "normalize"
81 (* By executing it - just type the advance command - you will see that the goal
82 has changed to west = west, by reducing the subexpression (opposite east).
83 You may use the retract bottom to undo the step, if you wish.
85 The new goal west = west is trivial: it is just a consequence of reflexivity.
86 Such trivial steps can be just closed in Matita by typing a double slash.
87 We complete the proof by the qed command, that instructs the system to store the
88 lemma performing some book-keeping operations.
93 (* In exactly the same way, we can prove that the opposite side of west is east.
94 In this case, we avoid the unnecessary simplification step: // will take care of
97 lemma west_to_east :
\ 5a href="cic:/matita/tutorial/chapter1/opposite.def(1)"
\ 6opposite
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6 \ 5a title="leibnitz's equality" href="cic:/fakeuri.def(1)"
\ 6=
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,1,0)"
\ 6east
\ 5/a
\ 6.
100 (* A slightly more complex problem consists in proving that opposite is
103 lemma idempotent_opposite : ∀x.
\ 5a href="cic:/matita/tutorial/chapter1/opposite.def(1)"
\ 6opposite
\ 5/a
\ 6 (
\ 5a href="cic:/matita/tutorial/chapter1/opposite.def(1)"
\ 6opposite
\ 5/a
\ 6 x)
\ 5a title="leibnitz's equality" href="cic:/fakeuri.def(1)"
\ 6=
\ 5/a
\ 6 x.
105 (* we start the proof moving x from the conclusion into the context, that is a
106 (backward) introduction step. Matita syntax for an introduction step is simply
107 the sharp character followed by the name of the item to be moved into the
108 context. This also allows us to rename the item, if needed: for instance if we
109 wish to rename x into b (since it is a bank), we just type #b. *)
113 (* See the effect of the execution in the goal window on the right: b has been
114 added to the context (replacing x in the conclusion); moreover its implicit type
115 "bank" has been made explicit.
117 But how are we supposed to proceed, now? Simplification cannot help us, since b
118 is a variable: just try to call normalize and you will see that it has no effect.
119 The point is that we must proceed by cases according to the possible values of b,
120 namely east and west. To this aim, you must invoke the cases command, followed by
121 the name of the hypothesis (more generally, an arbitrary expression) that must be
122 the object of the case analysis (in our case, b).
127 (* Executing the previous command has the effect of opening two subgoals,
128 corresponding to the two cases b=east and b=west: you may switch from one to the
129 other by using the hyperlinks over the top of the goal window.
130 Both goals can be closed by trivial computations, so we may use // as usual.
131 If we had to treat each subgoal in a different way, we should focus on each of
132 them in turn, in a way that will be described at the end of this section.
137 (* Instead of working with functions, it is sometimes convenient to work with
138 predicates. For instance, instead of defining a function computing the opposite
139 bank, we could declare a predicate stating when two banks are opposite to each
140 other. Only two cases are possible, leading naturally to the following
144 inductive opp :
\ 5a href="cic:/matita/tutorial/chapter1/bank.ind(1,0,0)"
\ 6bank
\ 5/a
\ 6 →
\ 5a href="cic:/matita/tutorial/chapter1/bank.ind(1,0,0)"
\ 6bank
\ 5/a
\ 6 → Prop ≝
145 | east_west : opp
\ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,1,0)"
\ 6east
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6
146 | west_east : opp
\ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,1,0)"
\ 6east
\ 5/a
\ 6.
148 (* In precisely the same way as "bank" is the smallest type containing east and
149 west, opp is the smallest predicate containing the two sub-cases east_west and
150 weast_east. If you have some familiarity with Prolog, you may look at opp as the
151 predicate definined by the two clauses - in this case, the two facts -
153 Between opp and opposite we have the following relation:
154 opp a b iff a = opposite b
155 Let us prove it, starting from the left to right implication, first *)
157 lemma opp_to_opposite: ∀a,b.
\ 5a href="cic:/matita/tutorial/chapter1/opp.ind(1,0,0)"
\ 6opp
\ 5/a
\ 6 a b → a
\ 5a title="leibnitz's equality" href="cic:/fakeuri.def(1)"
\ 6=
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/opposite.def(1)"
\ 6opposite
\ 5/a
\ 6 b.
159 (* We start the proof introducing a, b and the hypothesis opp a b, that we
163 (* Now we proceed by cases on the possible proofs of (opp a b), that is on the
164 possible shapes of oppab. By definition, there are only two possibilities,
165 namely east_west or west_east. Both subcases are trivial, and can be closed by
170 (* Let us come to the opposite direction. *)
172 lemma opposite_to_opp: ∀a,b. a
\ 5a title="leibnitz's equality" href="cic:/fakeuri.def(1)"
\ 6=
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/opposite.def(1)"
\ 6opposite
\ 5/a
\ 6 b →
\ 5a href="cic:/matita/tutorial/chapter1/opp.ind(1,0,0)"
\ 6opp
\ 5/a
\ 6 a b.
174 (* As usual, we start introducing a, b and the hypothesis (a = opposite b),
179 (* The right way to proceed, now, is by rewriting a into (opposite b). We do
180 this by typing ">eqa". If we wished to rewrite in the opposite direction, namely
181 opposite b into a, we would have typed "<eqa". *)
185 (* We conclude the proof by cases on b. *)
190 It is time to proceed with our formalization of the farmer's problem.
191 A state of the system is defined by the position of four item: the goat, the
192 wolf, the cabbage, and the boat. The simplest way to declare such a data type
196 record state : Type[0] ≝
197 {goat_pos :
\ 5a href="cic:/matita/tutorial/chapter1/bank.ind(1,0,0)"
\ 6bank
\ 5/a
\ 6;
198 wolf_pos :
\ 5a href="cic:/matita/tutorial/chapter1/bank.ind(1,0,0)"
\ 6bank
\ 5/a
\ 6;
199 cabbage_pos:
\ 5a href="cic:/matita/tutorial/chapter1/bank.ind(1,0,0)"
\ 6bank
\ 5/a
\ 6;
200 boat_pos :
\ 5a href="cic:/matita/tutorial/chapter1/bank.ind(1,0,0)"
\ 6bank
\ 5/a
\ 6}.
202 (* When you define a record named foo, the system automatically defines a record
203 constructor named mk_foo. To construct a new record you pass as arguments to
204 mk_foo the values of the record fields *)
206 definition start ≝
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,1,0)"
\ 6east
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,1,0)"
\ 6east
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,1,0)"
\ 6east
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,1,0)"
\ 6east
\ 5/a
\ 6.
207 definition end ≝
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6.
209 (* We must now define the possible moves. A natural way to do it is in the form
210 of a relation (a binary predicate) over states. *)
212 inductive move :
\ 5a href="cic:/matita/tutorial/chapter1/state.ind(1,0,0)"
\ 6state
\ 5/a
\ 6 →
\ 5a href="cic:/matita/tutorial/chapter1/state.ind(1,0,0)"
\ 6state
\ 5/a
\ 6 → Prop ≝
213 | move_goat: ∀g,g1,w,c.
\ 5a href="cic:/matita/tutorial/chapter1/opp.ind(1,0,0)"
\ 6opp
\ 5/a
\ 6 g g1 → move (
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 g w c g) (
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 g1 w c g1)
214 (* Every time g and g1 are two opposite banks, it is legal to put
215 the state "
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 g w c g", which says that goat and boat are on the same bank g,
216 and the state "
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 g1 w c g1", which says that goat and boat are on the same bank g1
217 in the relation "move" because, for example, moving the goat from bank g to bank g1 requires
218 moving the boat as well. *)
219 | move_wolf: ∀g,w,w1,c.
\ 5a href="cic:/matita/tutorial/chapter1/opp.ind(1,0,0)"
\ 6opp
\ 5/a
\ 6 w w1 → move (
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 g w c w) (
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 g w1 c w1)
220 | move_cabbage: ∀g,w,c,c1.
\ 5a href="cic:/matita/tutorial/chapter1/opp.ind(1,0,0)"
\ 6opp
\ 5/a
\ 6 c c1 → move (
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 g w c c) (
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 g w c1 c1)
221 | move_boat: ∀g,w,c,b,b1.
\ 5a href="cic:/matita/tutorial/chapter1/opp.ind(1,0,0)"
\ 6opp
\ 5/a
\ 6 b b1 → move (
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 g w c b) (
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 g w c b1).
223 (* A state is safe if either the goat is on the same bank of the boat, or both
224 the wolf and the cabbage are on the opposite bank of the goat. *)
226 inductive safe_state :
\ 5a href="cic:/matita/tutorial/chapter1/state.ind(1,0,0)"
\ 6state
\ 5/a
\ 6 → Prop ≝
227 | with_boat : ∀g,w,c.safe_state (
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 g w c g)
228 | opposite_side : ∀g,g1,b.
\ 5a href="cic:/matita/tutorial/chapter1/opp.ind(1,0,0)"
\ 6opp
\ 5/a
\ 6 g g1 → safe_state (
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 g g1 g1 b).
230 (* Finally, a state y is reachable from x if either there is a single move
231 leading from x to y, or there is a safe state z such that z is reachable from x
232 and there is a move leading from z to y *)
234 inductive reachable :
\ 5a href="cic:/matita/tutorial/chapter1/state.ind(1,0,0)"
\ 6state
\ 5/a
\ 6 →
\ 5a href="cic:/matita/tutorial/chapter1/state.ind(1,0,0)"
\ 6state
\ 5/a
\ 6 → Prop ≝
235 | one : ∀x,y.
\ 5a href="cic:/matita/tutorial/chapter1/move.ind(1,0,0)"
\ 6move
\ 5/a
\ 6 x y → reachable x y
236 | more : ∀x,z,y.
\ 5span style="text-decoration: underline;"
\ 6\ 5/span
\ 6reachable x z →
\ 5a href="cic:/matita/tutorial/chapter1/safe_state.ind(1,0,0)"
\ 6safe_state
\ 5/a
\ 6 z →
\ 5span style="text-decoration: underline;"
\ 6\ 5/span
\ 6\ 5a href="cic:/matita/tutorial/chapter1/move.ind(1,0,0)"
\ 6move
\ 5/a
\ 6 z y → reachable x y.
238 (* Remarkably, Matita is now able to solve the problem by itslef, provided
239 you allow automation to exploit more resources. The command /n/ is similar to
240 //, where n is a measure of this complexity: in particular it is a bound to
241 the depth of the expected proof tree (more precisely, to the number of nested
242 applicative nodes). In this case, there is a solution in six moves, and we
243 need a few more applications to handle reachability, and side conditions.
244 The magic number to let automation work is, in this case, 9. *)
246 lemma problem:
\ 5a href="cic:/matita/tutorial/chapter1/reachable.ind(1,0,0)"
\ 6reachable
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/start.def(1)"
\ 6start
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/end.def(1)"
\ 6end
\ 5/a
\ 6.
249 (* Let us now try to derive the proof in a more interactive way. Of course, we
250 expect to need several moves to transfer all items from a bank to the other, so
251 we should start our proof by applying "more".
254 lemma problem1:
\ 5a href="cic:/matita/tutorial/chapter1/reachable.ind(1,0,0)"
\ 6reachable
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/start.def(1)"
\ 6start
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/end.def(1)"
\ 6end
\ 5/a
\ 6.
255 normalize @
\ 5a href="cic:/matita/tutorial/chapter1/reachable.con(0,2,0)"
\ 6more
\ 5/a
\ 6
257 (* We have now four open subgoals:
260 Y : reachable [east,east,east,east] X
262 Z : move X [west,west,west,west]
264 That is, we must guess a state X, such that this is reachable from start, it is
265 safe, and there is a move leading from X to end. All goals are active, that is
266 emphasized by the fact that they are all red. Any command typed by the user is
267 normally applied in parallel to all active goals, but clearly we must proceed
268 here is a different way for each of them. The way to do it, is by structuring
269 the script using the following syntax: [...|... |...|...] where we typically have
270 as many cells inside the brackets as the number of the active subgoals. The
271 interesting point is that we can associate with the three symbol "[", "|" and
272 "]" a small-step semantics that allow to execute them individually. In particular
274 - the operator "[" opens a new focusing section for the currently active goals,
275 and focus on the first of them
276 - the operator "|" shift the focus to the next goal
277 - the operator "]" close the focusing section, falling back to the previous level
278 and adding to it all remaining goals not yet closed
280 Let us see the effect of the "[" on our proof:
285 (* As you see, only the first goal has now the focus on. Moreover, all goals got
286 a progressive numerical label, to help designating them, if needed.
287 We can now proceed in several possible ways. The most straightforward way is to
288 provide the intermediate state, that is [east,west,west,east]. We can do it, by
289 just applying this term. *)
291 @(
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,1,0)"
\ 6east
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,1,0)"
\ 6east
\ 5/a
\ 6)
293 (* This application closes the goal; at present, no goal has the focus on.
294 In order to act on the next goal, we must focus on it using the "|" operator. In
295 this case, we would like to skip the next goal, and focus on the trivial third
296 subgoal: a simple way to do it, is by retyping "|". The proof that
297 [east,west,west,east] is safe is trivial and can be done with //.*)
302 We then advance to the next goal, namely the fact that there is a move from
303 [east,west,west,east] to [west,west,west,west]; this is trivial too, but it
304 requires /2/ since move_goat opens an additional subgoal. By applying "]" we
305 refocus on the skipped goal, going back to a situation similar to the one we
310 (* Let us perform the next step, namely moving back the boat, in a sligtly
311 different way. The more operation expects as second argument the new
312 intermediate state, hence instead of applying more we can apply this term
313 already instatated on the next intermediate state. As first argument, we
314 type a question mark that stands for an implicit argument to be guessed by
317 @(
\ 5a href="cic:/matita/tutorial/chapter1/reachable.con(0,2,0)"
\ 6more
\ 5/a
\ 6 ? (
\ 5a href="cic:/matita/tutorial/chapter1/state.con(0,1,0)"
\ 6mk_state
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,1,0)"
\ 6east
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6))
319 (* We now get three independent subgoals, all actives, and two of them are
320 trivial. We
\ 5span style="font-family: Verdana,sans-serif;"
\ 6 \ 5/span
\ 6can just apply automation to all of them, and it will close the two
325 (* Let us come to the next step, that consists in moving the wolf. Suppose that
326 instead of specifying the next intermediate state, we prefer to specify the next
327 move. In the spirit of the previous example, we can do it in the following way
330 @(
\ 5a href="cic:/matita/tutorial/chapter1/reachable.con(0,2,0)"
\ 6more
\ 5/a
\ 6 … (
\ 5a href="cic:/matita/tutorial/chapter1/move.con(0,2,0)"
\ 6move_wolf
\ 5/a
\ 6 … ))
332 (* The dots stand here for an arbitrary number of implicit arguments, to be
333 guessed by the system.
334 Unfortunately, the previous move is not enough to fully instantiate the new
335 intermediate state: a bank B remains unknown. Automation cannot help here,
336 since all goals depend from this bank and automation refuses to close some
337 subgoals instantiating other subgoals remaining open (the instantiation could
338 be arbitrary). The simplest way to proceed is to focus on the bank, that is
339 the fourth subgoal, and explicitly instatiate it. Instead of repeatedly using "|",
340 we can perform focusing by typing "4:" as described by the following command. *)
342 [4: @
\ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,1,0)"
\ 6east
\ 5/a
\ 6] /2/
344 (* Alternatively, we can directly instantiate the bank into the move. Let
345 us complete the proof in this, very readable way. *)
347 @(
\ 5a href="cic:/matita/tutorial/chapter1/reachable.con(0,2,0)"
\ 6more
\ 5/a
\ 6 … (
\ 5a href="cic:/matita/tutorial/chapter1/move.con(0,1,0)"
\ 6move_goat
\ 5/a
\ 6 \ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6 … )) /2/
348 @(
\ 5a href="cic:/matita/tutorial/chapter1/reachable.con(0,2,0)"
\ 6more
\ 5/a
\ 6 … (
\ 5a href="cic:/matita/tutorial/chapter1/move.con(0,3,0)"
\ 6move_cabbage
\ 5/a
\ 6 ??
\ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,1,0)"
\ 6east
\ 5/a
\ 6 … )) /2/
349 @(
\ 5a href="cic:/matita/tutorial/chapter1/reachable.con(0,2,0)"
\ 6more
\ 5/a
\ 6 … (
\ 5a href="cic:/matita/tutorial/chapter1/move.con(0,4,0)"
\ 6move_boat
\ 5/a
\ 6 ???
\ 5a href="cic:/matita/tutorial/chapter1/bank.con(0,2,0)"
\ 6west
\ 5/a
\ 6 … )) /2/
350 @
\ 5a href="cic:/matita/tutorial/chapter1/reachable.con(0,1,0)"
\ 6one
\ 5/a
\ 6 /2/ qed.