+(**************************************************************************)
+(* ___ *)
+(* ||M|| *)
+(* ||A|| A project by Andrea Asperti *)
+(* ||T|| *)
+(* ||I|| Developers: *)
+(* ||T|| The HELM team. *)
+(* ||A|| http://helm.cs.unibo.it *)
+(* \ / *)
+(* \ / This file is distributed under the terms of the *)
+(* v GNU General Public License Version 2 *)
+(* *)
+(**************************************************************************)
+
+set "baseuri" "cic:/matita/didactic/ex_deriv".
+
+include "deriv.ma".
+
+theorem p_plus_p_p: ∀f:F. ∀g:F. (fpari f ∧ fpari g) → fpari (f ⊕ g).
+ assume f:F.
+ assume g:F.
+ suppose (fpari f ∧ fpari g) (h).
+ by h we have (fpari f) (H) and (fpari g) (K).
+ we need to prove (fpari (f ⊕ g))
+ or equivalently ((f ⊕ g) = (f ⊕ g) ∘ ρ).
+ conclude
+ (f ⊕ g)
+ = (f ⊕ (g ∘ ρ)) by _.
+ = ((f ∘ ρ) ⊕ (g ∘ ρ)) by _.
+ = ((f ⊕ g) ∘ ρ) by _
+ done.
+qed.
+
+theorem p_mult_p_p: ∀f:F. ∀g:F. (fpari f ∧ fpari g) → fpari (f · g).
+ assume f:F.
+ assume g:F.
+ suppose (fpari f ∧ fpari g) (h).
+ by h we have (fpari f) (H) and (fpari g) (K).
+ we need to prove (fpari (f · g))
+ or equivalently ((f · g) = (f · g) ∘ ρ).
+ conclude
+ (f · g)
+ = (f · (g ∘ ρ)) by _.
+ = ((f ∘ ρ) · (g ∘ ρ)) by _.
+ = ((f · g) ∘ ρ) by _
+ done.
+qed.
+
+theorem d_plus_d_d: ∀f:F. ∀g:F. (fdispari f ∧ fdispari g) → fdispari (f ⊕ g).
+ assume f:F.
+ assume g:F.
+ suppose (fdispari f ∧ fdispari g) (h).
+ by h we have (fdispari f) (H) and (fdispari g) (K).
+ we need to prove (fdispari (f ⊕ g))
+ or equivalently ((f ⊕ g) = (ρ ∘ ((f ⊕ g) ∘ ρ))).
+ conclude
+ (f ⊕ g)
+ = (f ⊕ (ρ ∘ (g ∘ ρ))) by _.
+ = ((ρ ∘ (f ∘ ρ)) ⊕ (ρ ∘ (g ∘ ρ))) by _.
+ = (((-R1) · (f ∘ ρ)) ⊕ (ρ ∘ (g ∘ ρ))) by _.
+ = (((i (-R1)) · (f ∘ ρ)) ⊕ ((i (-R1)) · (g ∘ ρ))) by _.
+ = (((f ∘ ρ) · (i (-R1))) ⊕ ((g ∘ ρ) · (i (-R1)))) by _.
+ = (((f ∘ ρ) ⊕ (g ∘ ρ)) · (i (-R1))) by _.
+ = ((i (-R1)) · ((f ⊕ g) ∘ ρ)) by _.
+ = (ρ ∘ ((f ⊕ g) ∘ ρ)) by _
+ done.
+qed.
+
+theorem d_mult_d_p: ∀f:F. ∀g:F. (fdispari f ∧ fdispari g) → fpari (f · g).
+ assume f:F.
+ assume g:F.
+ suppose (fdispari f ∧ fdispari g) (h).
+ by h we have (fdispari f) (h1) and (fdispari g) (h2).
+ we need to prove (fpari (f · g))
+ or equivalently ((f · g) = (f · g) ∘ ρ).
+ conclude
+ (f · g)
+ = (f · (ρ ∘ (g ∘ ρ))) by _.
+ = ((ρ ∘ (f ∘ ρ)) · (ρ ∘ (g ∘ ρ))) by _.
+ = (((-R1) · (f ∘ ρ)) · (ρ ∘ (g ∘ ρ))) by _.
+ = (((-R1) · (f ∘ ρ)) · ((-R1) · (g ∘ ρ))) by _.
+ = ((-R1) · (f ∘ ρ) · (-R1) · (g ∘ ρ)) by _.
+ = ((-R1) · ((f ∘ ρ) · (-R1)) · (g ∘ ρ)) by _.
+ = ((-R1) · (-R1) · (f ∘ ρ) · (g ∘ ρ)) by _.
+ = (R1 · ((f ∘ ρ) · (g ∘ ρ))) by _.
+ = (((f ∘ ρ) · (g ∘ ρ))) by _.
+ = ((f · g) ∘ ρ) by _
+ done.
+qed.
+
+theorem p_mult_d_p: ∀f:F. ∀g:F. (fpari f ∧ fdispari g) → fdispari (f · g).
+ assume f:F.
+ assume g:F.
+ suppose (fpari f ∧ fdispari g) (h).
+ by h we have (fpari f) (h1) and (fdispari g) (h2).
+ we need to prove (fdispari (f · g))
+ or equivalently ((f · g) = ρ ∘ ((f · g) ∘ ρ)).
+ conclude
+ (f · g)
+ = (f · (ρ ∘ (g ∘ ρ))) by _.
+ = ((f ∘ ρ) · (ρ ∘ (g ∘ ρ))) by _.
+ = ((f ∘ ρ) · ((-R1) · (g ∘ ρ))) by _.
+ = ((-R1) · ((f ∘ ρ) · (g ∘ ρ))) by _.
+ = ((-R1) · ((f · g) ∘ ρ)) by _.
+ = (ρ ∘ ((f · g) ∘ ρ)) by _
+ done.
+qed.
+
+theorem p_plus_c_p: ∀f:F. ∀x:R. fpari f → fpari (f ⊕ (i x)).
+ assume f:F.
+ assume x:R.
+ suppose (fpari f) (h).
+ we need to prove (fpari (f ⊕ (i x)))
+ or equivalently (f ⊕ (i x) = (f ⊕ (i x)) ∘ ρ).
+ by _ done.
+qed.
+
+theorem p_mult_c_p: ∀f:F. ∀x:R. fpari f → fpari (f · (i x)).
+ assume f:F.
+ assume x:R.
+ suppose (fpari f) (h).
+ we need to prove (fpari (f · (i x)))
+ or equivalently ((f · (i x)) = (f · (i x)) ∘ ρ).
+ by _ done.
+qed.
+
+theorem d_mult_c_d: ∀f:F. ∀x:R. fdispari f → fdispari (f · (i x)).
+ assume f:F.
+ assume x:R.
+ suppose (fdispari f) (h).
+ rewrite < fmult_commutative.
+ by _ done.
+qed.
+
+theorem d_comp_d_d: ∀f,g:F. fdispari f → fdispari g → fdispari (f ∘ g).
+ assume f:F.
+ assume g:F.
+ suppose (fdispari f) (h1).
+ suppose (fdispari g) (h2).
+ we need to prove (fdispari (f ∘ g))
+ or equivalently (f ∘ g = ρ ∘ ((f ∘ g) ∘ ρ)).
+ conclude
+ (f ∘ g)
+ = (ρ ∘ (f ∘ ρ) ∘ g) by _.
+ = (ρ ∘ (f ∘ ρ) ∘ ρ ∘ (g ∘ ρ)) by _.
+ = (ρ ∘ f ∘ (ρ ∘ ρ) ∘ (g ∘ ρ)) by _.
+ = (ρ ∘ f ∘ id ∘ (g ∘ ρ)) by _.
+ = (ρ ∘ ((f ∘ g) ∘ ρ)) by _
+ done.
+qed.
+
+theorem pari_in_dispari: ∀ f:F. fpari f → fdispari f '.
+ assume f:F.
+ suppose (fpari f) (h1).
+ we need to prove (fdispari f ')
+ or equivalently (f ' = ρ ∘ (f ' ∘ ρ)).
+ conclude
+ (f ')
+ = ((f ∘ ρ) ') by _. (*h1*)
+ = ((f ' ∘ ρ) · ρ ') by _. (*demult*)
+ = ((f ' ∘ ρ) · -R1) by _. (*deinv*)
+ = ((-R1) · (f ' ∘ ρ)) by _. (*fmult_commutative*)
+ = (ρ ∘ (f ' ∘ ρ)) (*reflex_ok*) by _
+ done.
+qed.
+
+theorem dispari_in_pari: ∀ f:F. fdispari f → fpari f '.
+ assume f:F.
+ suppose (fdispari f) (h1).
+ we need to prove (fpari f ')
+ or equivalently (f ' = f ' ∘ ρ).
+ conclude
+ (f ')
+ = ((ρ ∘ (f ∘ ρ)) ') by _.
+ = ((ρ ' ∘ (f ∘ ρ)) · ((f ∘ ρ) ')) by _.
+ = (((-R1) ∘ (f ∘ ρ)) · ((f ∘ ρ) ')) by _.
+ = (((-R1) ∘ (f ∘ ρ)) · ((f ' ∘ ρ) · (-R1))) by _.
+ = ((-R1) · ((f ' ∘ ρ) · (-R1))) by _.
+ = (((f ' ∘ ρ) · (-R1)) · (-R1)) by _.
+ = ((f ' ∘ ρ) · ((-R1) · (-R1))) by _.
+ = ((f ' ∘ ρ) · R1) by _.
+ = (f ' ∘ ρ) by _
+ done.
+qed.
+
+(*
+alias id "plus" = "cic:/matita/nat/plus/plus.con".
+theorem de_prodotto_funzioni:
+ ∀ n:nat. (id ^ (plus n (S O))) ' = (i (n + (S O))) · (id ^ n).
+ assume n:nat.
+ we proceed by induction on n to prove
+ ((id ^ (plus n (S O))) ' = (i (n + (S O))) · (id ^ n)).
+ case O.
+ we need to prove ((id ^ (plus O (S O))) ' = (i (S O)) · (id ^ O)).
+ conclude
+ ((id ^ (plus O (S O))) ')
+ = ((id ^ (S O)) ') by _.
+ = ((id · (id ^ O)) ') by _.
+ = ((id · (i R1)) ') by _.
+ = (id ') by _.
+ = (i R1) by _.
+ = (i R1 · i R1) by _.
+ = (i (R0 + R1) · R1) by _.
+ = ((i (S O)) · (id ^ O)) by _
+ done.
+ case S (n:nat).
+ by induction hypothesis we know
+ ((id ^ (plus n (S O))) ' = (i (n + (S O))) · (id ^ n)) (H).
+ we need to prove
+ ((id ^ (plus (plus n (S O)) (S O))) '
+ = (i (plus (plus n (S O)) (S O))) · (id ^ (plus n (S O)))).
+ conclude
+ ((id ^ ((n + (S O)) + (S O))) ')
+ = ((id ^ ((n + (S (S O))))) ') by _.
+ = ((id ^ (S (n + S O))) ') by _.
+ = ((id · (id ^ (n + (S O)))) ') by _.
+ = ((id ' · (id ^ (n + (S O)))) ⊕ (id · (id ^ (n + (S O))) ')) by _.
+ alias symbol "plus" (instance 4) = "natural plus".
+ = ((R1 · (id ^ (n + (S O)))) ⊕ (id · ((i (n + S O)) · (id ^ n)))) by _.
+ = ((R1 · (id ^ (n + (S O)))) ⊕ (((i (n + S O)) · id · (id ^ n)))) by _.
+ alias symbol "plus" (instance 8) = "natural plus".
+ = ((R1 · (id ^ (n + (S O)))) ⊕ ((i (n + S O)) · (id ^ (n + (S O))))) by _.
+ = ((i R1 · (id ^ (n + (S O)))) ⊕ ((i (n + S O)) · (id ^ (n + (S O))))) by _.
+ alias symbol "plus" = "natural plus".
+ cut (((i R1 · (id ^ (n + (S O)))) ⊕ ((i (n + S O)) · (id ^ (n + (S O))))) =
+ (((i R1 ⊕ (i (plus n (S O)))) · (id ^ (n + (S O))))));[| by _ done;]
+ unfold F_OF_nat in Hcut;
+ rewrite > Hcut;
+ = (((i R1 ⊕ (i (plus n (S O)))) · (id ^ (n + (S O))))) by _.
+ = ((i (n + S O + S O)) · (id ^ (n + S O))) by _
+ done.
+qed.
+*)
+
+let rec times (n:nat) (x:R) on n: R ≝
+ match n with
+ [ O ⇒ R0
+ | S n ⇒ Rplus x (times n x)
+ ].
+
+axiom invS: nat→R.
+axiom invS1: ∀n:nat. Rmult (invS n) (real_of_nat (n + S O)) = R1.
+axiom invS2: invS (S O) + invS (S O) = R1. (*forse*)
+
+axiom e:F.
+axiom deriv_e: e ' = e.
+axiom e1: e · (e ∘ ρ) = R1.
+
+(*
+theorem decosh_senh:
+ (invS (S O) · (e ⊕ (e ∘ ρ)))' = (invS (S O) · (e ⊕ (ρ ∘ (e ∘ ρ)))).
+*)
\ No newline at end of file