Those problems can be separated, but picking a different
term to diverge
C y (x C a) (x @ C)\r
C y (x @ @) (x b C)\r
\r
-$! simple.constants.1/1\r
-D y (x (y C))\r
-C y (x @)\r
+#is this the problem that requires to make\r
+# x (y C) diverge instead?\r
+#$! simple.constants.1/1\r
+#D y (x (y C))\r
+#C y (x @)\r
\r
-$! simple.constants.1/1'\r
-D y (z. x (y C))\r
-C y (z. x z)\r
+#is this the problem that requires to make\r
+# x (y C) diverge instead?\r
+#$! simple.constants.1/1'\r
+#D y (z. x (y C))\r
+#C y (z. x z)\r
\r
$! simple.constants.1/2\r
D y (x (y C (x C)))\r