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Optimization: since an invariant says that the inferred type of a term is
authorClaudio Sacerdoti Coen <claudio.sacerdoticoen@unibo.it>
Thu, 26 Feb 2004 12:01:27 +0000 (12:01 +0000)
committerClaudio Sacerdoti Coen <claudio.sacerdoticoen@unibo.it>
Thu, 26 Feb 2004 12:01:27 +0000 (12:01 +0000)
always a type, then we do not have to call the sort_of_prod to check the
the type of a lambda-abstraction is a well-typed prod. We just have to check
that the source of the lambda is a sort (or a meta).


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