Added an example (well founded recursion).

[helm.git] / helm / papers / system_T / t.tex

\documentclass[a4paper]{article}
\pagestyle{headings}
%\usepackage{graphicx}
\usepackage{amssymb,amsmath,mathrsfs,stmaryrd,amsthm}
%\usepackage{hyperref}
%\usepackage{picins}

\newcommand{\semT}[1]{\ensuremath{\llbracket #1 \rrbracket}}
\newcommand{\sem}[1]{\llbracket \ensuremath{#1} \rrbracket}
\newcommand{\R}{\;\mathscr{R}\;}
\newcommand{\N}{\,\mathbb{N}\,}
\newcommand{\NT}{\,\mathbb{N}\,}
\newcommand{\NH}{\,\mathbb{N}\,}
\renewcommand{\star}{\ast}
\renewcommand{\vec}{\overrightarrow}
\newcommand{\one}{\mathscr{1}}
\newcommand{\mult}{\cdot}
\newcommand{\ind}{Ind(X)}
\newcommand{\Xind}{\ensuremath{X_{ind}}}
\renewcommand{\|}{\ensuremath{\quad | \quad}}
\newcommand{\triUP}{\ensuremath{\Delta}}
\newcommand{\triDOWN}{\ensuremath{\nabla}}
\newcommand{\Rx}{\ensuremath{R_X}}

\newtheorem{thm}{Theorem}[subsection]

\title{Modified Realizability and Inductive Types}
\author{...}


\begin{document}
\maketitle

\begin{abstract}
...
\end{abstract}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\section{Introduction}
The characterization of the provable recursive functions of 
Peano Arithmetic as the terms of system T is a well known
result of G\"odel \cite{Godel58,Godel90}. Although several authors acknowledge 
that the functional interpretation of the Dialectica paper
is not among the major achievements of the author (see e.g. \cite{Girard87}), 
the result has been extensively investigated and there is a wide 
literature on the 
topic (see e.g. \cite{Howard68,Troelstra,Girard87}. 

A different, more neglected, but for many respects much more 
direct relation between Peano (or Heyting) Arithmetics and 
G\"odel System T is provided
by the so called {\em modified realizability}. Modified realizability
was first introduced by Kreisel in \cite{Kreisel59} - although it will take you
a bit of effort to recognize it in the few lines of paragraph 3.52 -
and later in \cite{Kreisel62} under the name of generalized realizability.
The name of modified realizability seems to be due to Troelstra 
\cite{Troelstra}
- who contested Kreisel's name but unfortunately failed in proposing 
a valid alternative; we shall reluctantly adopt this latter name 
to avoid further confusion. Modified realizability is a typed variant of 
realizability, essentially providing interpretations 
of $HA^{\omega}$ into itself: each theorem is realized by a typed function
of system T, that also gives the actual computational content extracted 
from the proof. 
In spite of the simplicity and the elegance of the proof, it is extremely
difficult to find a modern discussion of this result; the most recent
exposition we are aware of is in the encyclopedic (typewritten!) work by
Troelstra \cite{Troelstra} (pp.213-229). Even modern introductory books
to Type Theory and Proof Theory devoting much space to system T
such as \cite{GLT} and \cite{TS} surprisingly leave out this simple and 
illuminating result. Both \cite{GLT} and \cite{TS}
prefer to focus on higher order arithmetics and its relation with 
Girard's System $F$ \cite{Girard86}, but the technical complexity and
the didactical value of the two proofs is not comparable: when you 
prove that the Induction Principle is realized by the recursor $R$ 
of system $T$ you catch a sudden gleam of understanding in the 
students eyes; usually, the same does not happen when you show, say, 
that the ``forgetful'' interpretation of the higher order predicate defining
the natural numbers is the system $F$ encoding 
$\forall X.(X\to X) \to X \to X$ of $\N$. 
Moreover, after a first period of enthusiasm, the impredicative 
encoding of inductive types in Logical Frameworks has shown several 
problems and limitations (see e.g. \cite{Werner} pp.24-25) mostly
solved by assuming inductive types as a primitive logical notion
(leading e.g. form the Calculus of Constructions to the Calculus
of Inductive Constructions - CIC). Even the extraction algorithm of
CIC, strictly based on realizability principles, and in a first time
still oriented towards System F \cite{Paulin87,Paulin89} has been 
recently rewritten \cite{Letouzey04}
to take advantage of concrete types and pattern matching of ML-like
languages. Unfortunately, systems like the Calculus of Inductive 
Constructions are so complex, from the logical point of view, to 
substantially prevent a really neat theoretical exposition (at present, 
it does not
even exists a truly complete consistency proofs covering all aspects
of such systems); moreover, not everybody may be interested in all the features
offered by these frameworks, from polymorphism to types depending on 
proofs. Our program is to restart the analysis of logical systems with
primitive inductive types in a smooth way, starting form first order
logic and adding little by little small bits of logical power.
This paper is the first step in this direction.

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\section{Heyting's arithmetics}

{\bf Axioms}

\begin{itemize}
\item $nat\_ind: P(0) \to (\forall x.P(x) \to P(S(x))) \to \forall x.P(x)$ 
\item $ex\_ind: (\forall x.P(x) \to Q) \to \exists x.P(x) \to Q$
\item $ex\_intro: \forall x.(P \to \exists x.P)$
\item $fst: P \land Q \to P$
\item $snd: P \land Q \to Q$
\item $conj: P \to Q \to P \land Q$
\item $false\_ind: \bot \to Q$
\item $discriminate:\forall x.0 = S(x) \to \bot$
\item $injS: \forall x,y.S(x) = S(y) \to x=y$
\item $plus\_O:\forall x.x+0=x$
\item $plus\_S:\forall x,y.x+S(y)=S(x+y)$ 
\item $times\_O:\forall x.x\mult0=0$
\item $times\_S:\forall x,y.x\mult S(y)=x+(x\mult y)$ 
\end{itemize}

\noindent
{\bf Inference Rules}

say that ax:AX refers to the previous Axioms list...

\[
  (Proj)\hspace{0.2cm} \Gamma, x:A, \Delta \vdash x:A
  \hspace{2cm}
  (Const)\hspace{0.2cm} \Gamma \vdash ax : AX
\]

\[ 
   (\to_i)\hspace{0.2cm}\frac{\Gamma,x:A \vdash M:Q}{\Gamma \vdash \lambda x:A.M: A \to Q} \hspace{2cm}
   (\to_e)\hspace{0.2cm}\frac{\Gamma \vdash M: A \to Q \hspace{1cm}\Gamma \vdash N: A}
    {\Gamma \vdash M N: Q} 
\]

%\[ 
%   (\land_i)\frac{\Gamma \vdash M:A \hspace{1cm}\Gamma \vdash N:B}
%   {\Gamma \vdash <M,N> : A \land B} 
%\hspace{2cm}
%   (\land_{el})\frac{\Gamma \vdash A \land B}{\Gamma \vdash A}
%\hspace{2cm}
%   (\land_{er})\frac{\Gamma \vdash A \land B}{\Gamma \vdash B}  
%\]

\[ 
   (\forall_i)\hspace{0.2cm}\frac{\Gamma \vdash M:P}{\Gamma \vdash 
   \lambda x:\N.M: \forall x.P}(*) \hspace{2cm}
   (\forall_e)\hspace{0.2cm}\frac{\Gamma \vdash M :\forall x.P}{\Gamma \vdash M t: P[t/x]} 
\]


%\[ 
%   (\exists_i)\frac{\Gamma \vdash P[t/x]}{\Gamma \vdash \exists x.P}\hspace{2cm}
%   (\exists_e)\frac{\Gamma \vdash \exists x.P\hspace{1cm}\Gamma \vdash \forall x.P \to Q}
%{\Gamma \vdash Q} 
%\]

\section{Extraction}

The formulae to types translation function 
$\sem{\cdot}$ takes in input formulae in HA and returns types in T.

\begin{enumerate}
\item $\sem{A} = \one$ if A is atomic
\item $\sem{A \land B} = \sem{A}\times \sem{B}$
\item $\sem{A \to B} = \sem{A}\to \sem{B}$
\item $\sem{\forall x:\N.P} = \N \to \sem{P}$
\item $\sem{\exists x:\N.P} = \N \times \sem{P}$
\end{enumerate}

definition.
For any type T of system T $\bot_T: \one \to T$  is inductively defined as follows:
\begin{enumerate}
\item $\bot_\one = \lambda x:\one.x$
\item $\bot_N = \lambda x:\one.0$
\item $\bot_{U\times V} = \lambda x:\one.<\bot_{U} x,\bot_{V} x>$
\item $\bot_{U\to V} = \lambda x:\one.\lambda \_:U. \bot_{V} x$
\end{enumerate}

\begin{itemize}
\item $\sem{nat\_ind} = R$
\item $\sem{ex\_ind} = (\lambda f:(\N \to \sem{P} \to \sem{Q}).
\lambda p:\N\times \sem{P}.f (fst \,p) (snd \,p)$. 
\item $\sem{ex\_intro} = \lambda x:\N.\lambda f:\sem{P}.<x,f>$
\item $\sem{fst} = \pi_1$
\item $\sem{snd} = \pi_2$
\item $\sem{conj} = \lambda x:\sem{P}.\lambda y:\sem{Q}.<x,y>$
\item $\sem{false\_ind} = \bot_{\sem{Q}}$
\item $\sem{discriminate} = \lambda \_:\N.\lambda \_:\one.\star$
\item $\sem{injS}= \lambda \_:\N. \lambda \_:\N.\lambda \_:\one.\star$
\item $\sem{plus\_O} = \sem{times\_O} = \lambda \_:\N.\star$
\item $\sem{plus\_S} = \sem{times_S} = \lambda \_:\N. \lambda \_:\N.\star$
\end{itemize}

In the case of structured proofs:
\begin{itemize}
\item $\semT{M N} = \semT{M} \semT{N}$
\item $\semT{\lambda x:A.M} = \lambda x:\sem{A}.\semT{M}$
\item $\semT{\lambda x:\N.M} = \lambda x:\N.\semT{M}$
\item $\semT{M t} = \semT{M} \semT{t}$
\end{itemize}

\section{Realizability}
The realizability relation is a relation $f \R P$ where $f: \sem{P}$, and
$P$ is a closed formula.
In particular:
\begin{itemize}
\item $\neg (\star \R \bot)$
\item $* \R (t_1=t_2)$ iff $t_1=t_2$ is true ...
\item $<f,g> \R (P\land Q)$ iff $f \R P$ and $g \R Q$
\item $f \R (P\to Q)$ iff for any $m$ such that $m \R P$, $(f \,m) \R Q$
\item $f \R (\forall x.P)$ iff for any natural number $n$ $(f n) \R P[\underline{n}/x]$
\item $<n,g> \R (\exists x.P)$ iff $g \R P[\underline{n}/x]$
\end{itemize}
%We need to generalize the notion of realizability to sequents.
%Given a sequent $B_1, \ldots, B_n \vdash A$ with free variables in 
%$\vec{x} = x_1,\ldots, x_m$, we say that $f \R B1, \ldots, B_n \vdash A$ iff 
%forall natural numbers $n_1, \ldots, n_m$, 
%if forall $i \in {1,\ldots,n}$ 
%$m_i \R B_i[\vec{\underline{n}}/\vec{x}]$ then
%$$f <m_1, \ldots, m_n> \R A[\vec{\underline{n}}/\vec{x}]$$.
%
\noindent
We need to generalize the notion of realizability to sequents.\\
Let $\vec{x} = FV_{\N}( B_1, \ldots, B_n, P)$ a vector of variables of type
$\N$ that occur free in $B_1, \ldots, B_n, P$. Let $\vec{b:B}$ the vector
$b_1:B_1, \ldots, b_n:B_n$.\\ 
We say that $f \R B_1, \ldots, B_n \vdash A:P$ iff
$$\lambda \vec{x:\N}. \lambda \vec{b:B}.f \R 
\forall \vec{x}. B_1 \to \ldots \to B_n \to P$$
Note that $\forall \vec{x}. B_1 \to \ldots \to B_n \to P$ is a closed formula,
so we can use the previous definition of realizability on it.

\noindent
We proceed to prove that all axioms $ax:Ax$ are realized by $\sem{ax}$.

\begin{itemize}
\item $nat\_ind$. 
  We must prove that the recursion schema $R$ realizes the induction principle.
  To this aim we must prove that for any $a$ and $f$ such that $a \R P(0)$ and
  $f \R \forall x.(P(x) \to P(S(x)))$, and any natural number $n$, $(R \,a \,f
  \,n) \R P(\underline{n})$.\\ 
  We proceed by induction on n.\\ 
  If $n=O$, $(R \,a \,f \,O) = a$ and by hypothesis $a \R P(0)$.\\ 
  Suppose by induction that
  $(R \,a \,f \,n) \R P(\underline{n})$, and let us prove that the relation
  still holds for $n+1$.  By definition 
  $(R \,a \,f \,(n+1)) = f \,n \,(R \,a \,f \,n)$, 
  and since $f \R \forall x.(P(x) \to P(S(x)))$,  
  $(f n (R a f n)) \R P(S(\underline{n}))=P(\underline{n+1})$.

\item $ex\_ind$. 
  We must prove that $$\underline{ex\_ind} \R (\forall x:(P x)
  \to Q) \to (\exists x:(P x)) \to Q$$ Following the definition of $\R$ we have
  to prove that given\\ $f~\R~\forall~x:((P~x)~\to~Q)$ and
  $p~\R~\exists~x:(P~x)$, then $\underline{ex\_ind}~f~p \R Q$.\\ 
  $p$ is a couple $<n_p,g_p>$ such that $g_p \R P[\underline{n_p}/x]$, while
  $f$ is a function such that forall $n$ and for all $m \R P[\underline{n}/x]$
  then $f~n~m \R Q$ (note that $x$ is not free in $Q$ so $[\underline{n}/x]$
  affects only $P$).\\
  Expanding the definition of $\underline{ex\_ind}$, $fst$
  and $snd$ we obtain $f~n_p~g_p$ that we know is in relation $\R$ with $Q$
  since $g_p \R P[\underline{n_p}/x]$.

\item $ex\_intro$.
  We must prove that 
  $$\lambda x:\N.\lambda f:\sem{P}.<x,f> \R \forall x.(P\to\exists x.P(x)$$
  that leads to prove that for each n
  $\underline{ex\_into}~n \R (P\to\exists x.P(x))[\underline{n}/x]$.\\
  Evaluating the substitution we have 
  $\underline{ex\_into}~n \R (P[\underline{n}/x]\to\exists x.P(x))$.\\
  Again by definition of $\R$ we have to prove that given a 
  $m \R P[\underline{n}/x]$ then $\underline{ex\_into}~n~m \R \exists x.P(x)$.
  Expanding the definition of $\underline{ex\_intro}$ we have
  $<n,m> \R \exists x.P(x)$ that is true since $m \R P[\underline{n}/x]$.

\item $fst$.
  We have to prove that $\pi_1 \R P \land Q \to P$, that is equal to proving
  that for each $m \R P \land Q$ then $\pi_1~m \R P$ .
  $m$ must be a couple $<f_m,g_m>$ such that $f_m \R P$ and $g_m \R Q$.
  So we conclude that $\pi_1~m$ reduces to $f_m$ that is in relation $\R$
  with $P$.

\item $snd$. The same for $fst$.

\item $conj$. 
  We have to prove that 
  $$\lambda x:\sem{P}. \lambda y:\sem{Q}.<x,y> \R P \to Q \to P \land Q$$
  Following the definition of $\R$ we have to show that 
  for each $m \R P$ and for each $n \R Q$ then 
  $(\lambda x:\sem{P}. \lambda y:\sem{Q}.<x,y>)~m~n \R P \land Q$.\\
  This is the same of $<m,n> \R P \land Q$ that is verified since 
  $m \R P$ and $n \R Q$.


\item $false\_ind$. 
  We have to prove that $\bot_{\sem{Q}} \R \bot \to Q$. 
  Trivial, since there is no $m \R \bot$.

\item $discriminate$. 
  Since there is no $n$ such that $0 = S n$ is true... \\
  $\underline{discriminate}~n \R 0 = S~\underline{n} \to \bot$ for each n.

\item $injS$.
  We have to prove that for each $n_1$ and $n_2$\\
  $\lambda \_:\N. \lambda \_:\N.\lambda \_:\one.*~n_1~n_2 \R 
  (S(x)=S(y)\to x=y)[n_1/x][n_2/y]$.\\
  We assume that $m \R S(n_1)=S(n_2)$ and we have to show that 
  $\lambda \_:\N. \lambda \_:\N.\lambda \_:\one.*~n_1~n_2~m$ that reduces to
  $*$ is in relation $\R$ with $n_1=n_2$. Since in the standard model of 
  natural numbers  $S(n_1)=S(n_2)$ implies $n_1=n_2$ we have that 
  $* \R n_1=n_2$.

\item $plus\_O$. 
  Since in the standard model for natural numbers $0$ is the neutral element
  for addition $\lambda \_:\N.\star \R \forall x.x + 0 = x$.

\item $plus\_S$.
  In the standard model of natural numbers the addition of two numbers is the 
  operation of counting the second starting from the first. So
  $$\lambda \_:\N. \lambda \_:\N. \star \R \forall x,y.x+S(y)=S(x+y)$$.

\item $times\_O$.
  Since in the standard model for natural numbers $0$ is the absorbing element
  for multiplication $\lambda \_:\N.\star \R \forall x.x \mult 0 = 0$.
  
\item $times\_S$.
  In the standard model of natural numbers the multiplications of two 
  numbers is the operation of adding the first to himself a number of times
  equal to the second number. So
  $$\lambda \_:\N. \lambda \_:\N. \star \R \forall x,y.x+S(y)=S(x+y)$$.
  
\end{itemize}


\noindent
{\bf example}\\
Let us prove the following principle of well founded induction:
\[(\forall m.(\forall p. p < m \to P p) \to P m) \to \forall n.P n\]
In the following proof we shall make use of proof-terms, since we finally
wish to extract the computational content; we leave to reader the easy
check that the proof object describes the usual and natural proof
of the statement.

We assume to have already proved the following lemmas (having trivial
realizers):\\
\[L: \lambda b.p < 0 \to \bot\]
\[M: \lambda p,q,n.p < q \to q \le (S n) \to p \le n \]
Let us assume $h: \forall m.(\forall p. p < m \to P p) \to P m$.
We prove by induction on n that $\forall q. q \le n \to P q$.
For $n=0$, we get a proof of $P \;0$ by 
\[ B: \lambda q.\lambda \_:q \le n. h \;0\; 
(\lambda p.\lambda k:p < 0. false\_ind \;(L\;p\; k)) \]
In the inductive case, we must prove that, for any n, 
\[(\forall q. q \le n \to P q) \to (\forall q. q \le S n \to P q)\]
Assume $h1: \forall q. q \le n \to P q$ and
$h2: q \le S \;n$. Let us prove $\forall p. p < q \to P p$.
If $h3: p < q$ then $(M\; p\; q\; n\; h3\; h2): p \le n$, hence 
$h1 \;p \; (M\; p\; q\; n\; h3\; h2): P p$.\\ 
In conclusion, the proof of the 
inductive case is
\[I: \lambda h1:\forall q. q \le n \to P\; q.\lambda q.\lambda h2:q \le S n.
h \; q \; (\lambda p.\lambda h3:p < q.h1 \;p\; (M\; p\; q\; n\; h3\; h2)) \]
(where $h$ is free in I).
The full proof is
\[ \lambda m.\lambda h: \forall m.(\forall p. p < m \to P p) \to P m.
nat\_ind \;B \; I \;m\; (le\_n \; m) \]
where $le\_n$ is a proof that $\forall n. n \le n$.\\
Form the previous proof,after stripping terminal objects, 
and a bit of eta-contraction to make
the term more readable, we extract the following term (types are omitted):

\[R' = \lambda m.\lambda f.
R\; (f \; O\; (\lambda q.*_A))\; 
(\lambda n\lambda g\lambda q.f \;q\;g)\;m \;m\]

The intuition of this operator is the following: supose to
have a recursive definition $h q = F[h]$ where $q:\N$ and 
$F[h]: A$. This defines a functional 
$f: \lambda q.\lambda g.F[g]: N\to(N\to A) \to A$, such that
(morally) $h$ is the fixpoint of $f$. For instance, 
in the case of the fibonacci function, $f$ is 
\[\lambda q. \lambda g.
if\; q = 0\;then\; 1\; else\; if\; q = 1\; then\; 1\; else\; g (q-1)+g (q-2)\]

So $f$ build a new 
approximation of $h$ from the previous approximation $h$ taken
as input. $R'$ precisely computes the mth-approximation starting
from a dummy function $(\lambda q.*_A)$. Alternatively, 
you may look at $g$ as the ``history'' (curse of values) of $h$ 
for all values less or equal to $q$; then $f$ extend $g$ to
$q+1$.

\section{Inductive types}
The notation we will use is similar to the one used in 
\cite{Werner} and \cite{Paulin89} but we prefer
giving a label to each constructor and use that label instead of the
longer $Constr(n,\ind\{\ldots\})$ to indicate the $n^{th}$ constructor.
We adopt the vector notation to make things more readable.
$\vec{m}$ has to be intended as $m_1~\ldots~m_n$ where $n$ may
be equal to 0 (we use $m_1~\vec{m}$ when we want to give a
name to the first $m$ and assert $n>0$). If the vector notation is
used inside an arrow type it has a slightly different meaning, 
$A \to \vec{B} \to C$ is a shortcut for 
$A \to B_1 \to \ldots \to B_n \to C$.

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\subsection{Extensions to the logic framework}
To talk about arbitrary inductive types (and not hard coded natural numbers) we
have to extend a bit our framework.

First we admit quantification over inductive types $T$, thus $\forall x:T.A$
and $\exists x:T.A$ are allowed. Then rules 4 and 5 of the $\sem{\cdot}$
definition are replaced by $\sem{\forall x:T.P} = T \to \sem{P}$ and
$\sem{\exists x:T.P} = T \times \sem{P}$.

For each inductive type we will describe the formation rules and the
corresponding induction principle schema.

Symmetrically we have to extend System T with arbitrary inductive types and 
we will see how theyr recursors are defined in the following sections. 

The definition of $\R$ is modified substituting each occurrence of $\N$ with 
a generic inductive type $T$.

%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\subsection{Type definition}
$$\ind\{c_1:C(X); \ldots ; c_n:C(X)\}$$
$$C(X) ::= X \| T \to C(X) \| X \to C(X)$$
In the second case we mean $T \neq X$.

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\subsection{Induction principle}
The induction principle for an inductive type $X$ and a predicate $Q$ 
is a constant with the following type
$$\Xind:\vec{\triUP\{C(X), c\}} \to \forall t:X.Q(x)$$
$\triUP$ takes a constructor type $C(X)$ and a term $c$ (initially $c$ is a
constructor of X, and $c:C(X)$) and is defined by recursion as follows:
\begin{eqnarray}
\triUP\{X, c\} & = & Q(c) \nonumber\\
\triUP\{T \to C(X), c\} & = & 
        \forall m:T.\triUP\{C(X),c~m\} \nonumber\\
\triUP\{X \to C(X), c\} & = & 
        \forall t:X.Q(t) \to \triUP\{C(X), c~t\} \nonumber
\end{eqnarray}

%%%%%%%%%%%%%%%%%%%%%
\subsection{Recursor}
\subsubsection{Type}
The type of the recursor $\Rx$ on an inductive type $X$ is
$$\Rx : \vec{\square\{C(X)\}} \to X \to \alpha$$
$\square$ is defined by recursion on the constructor type $C(X)$.
\begin{eqnarray}
\square\{X\} & = & \alpha \nonumber \\
\square\{T \to C(X)\} & = & T \to \square\{C(X)\}\nonumber \\
\square\{X \to C(X)\} & = & X \to \alpha \to \square\{C(X)\}\nonumber 
\end{eqnarray}
\subsubsection{Reduction rules}
We say that 
$$\Rx~\vec{f}~(c_i~\vec{m}) \leadsto
\triDOWN\{C(X)_i, f_i, \vec{m}\}$$
$\triDOWN$ takes a constructor type $C(X)$, a term $f$ 
(of type $\square\{C(X)\}$) and is defined by recursion as follows:
\begin{eqnarray}
\triDOWN\{X, f, \} & = & f\nonumber \\
\triDOWN\{T \to C(X), f, m_1~\vec{m}\} & = &
        \triDOWN\{C(X), f~m_1, \vec{m}\}\nonumber \\
\triDOWN\{X \to C(X), f, m_1~\vec{m}\} & = & 
        \triDOWN\{C(X), f~m_1~(\Rx~\vec{f}~m_1),
        \vec{m}\}\nonumber
\end{eqnarray}
We assume $\Rx~\vec{f}~(c_i~\vec{m})$ is well typed, so in the first case we
can omit $\vec{m}$ since it is an empty sequence.

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\subsection{Realizability of the induction principle}
Once we have inductive types and their induction principle we want to show that
the recursor $\Rx$ realizes $\Xind$, that is that $\Rx$ has type 
$\sem{\Xind}$ and is in relation $\R$ with $\Xind$. 

\begin{thm}$\Rx : \sem{\Xind}$\end{thm}
\begin{proof}
We have to compare the definition of $\square$ and $\triUP$
since they play the same role in constructing respectively the types of 
$\Rx$ and
$\Xind$. If we assume $\alpha = \sem{Q}$ and we apply the $\sem{\cdot}$
function to each right side of the $\triUP$ definition we obtain
exactly $\square$. The last two elements of the arrows $\Rx$ and
$\Xind$ are again the same up to $\sem{\cdot}$.
\end{proof}

\begin{thm}$\Rx\R \Xind$\end{thm}
\begin{proof}
To prove that $\Rx\R \Xind$ we must assume that for each $i$ index
of a constructor of $X$, $f_i \R \triUP\{C(X)_i, c_i\}$ and we
have to prove that for each $t:X$
$$\Rx~\vec{f}~t \R Q(t)$$
\noindent
We proceed by induction on the structure of $t$.
\\
The base case is when the
type of the head constructor of $t$ has no recursive arguments (i.e. the type
is generated using only the first two rules $C(X)$), so
$(\Rx~\vec{f}~(c_i~\vec{m}))$ reduces in one step to $(f_i~\vec{m})$.  $f_i$
realizes $\triUP\{C(X)_i, c_i\}$ by assumption and since we are in the base
case $\triUP\{C(X)_i, c_i\}$ is of the form $\vec{\forall t:T}.Q(c_i~\vec{t})$.
Thus $f_i~\vec{m} \R Q(c_i~\vec{m})$.
\\ 
In the induction step we have as induction hypothesis that for each recursive
argument $t_i$ of the head constructor $c_i$, $r_i\equiv
\Rx~\vec{f}~t_i \R Q(t_i)$. By the third rule of $\triDOWN$ we obtain the reduct
$f_i~\vec{m}~\vec{t~r}$ (here we write first all the non recursive arguments,
then all the recursive one. In general they can be mixed and the proof is
exactly the same but the notation is really heavier). We know by hypothesis
that $f_i \R \triUP\{C(X)_i, c_i\} \equiv \vec{\forall m:T}.\vec{\forall
t:X.Q(t)} \to Q(c_i~\vec{m}~\vec{t})$, thus $f_i~\vec{m}~\vec{t~r} \R
Q(c_i~\vec{m}~\vec{t})$.
\end{proof}


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\end{document}